(8y^2-28y)/(4y^2-20y)

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Solution for (8y^2-28y)/(4y^2-20y) equation:


D( y )

4*y^2-(20*y) = 0

4*y^2-(20*y) = 0

4*y^2-(20*y) = 0

4*y^2-20*y = 0

4*y^2-20*y = 0

DELTA = (-20)^2-(0*4*4)

DELTA = 400

DELTA > 0

y = (400^(1/2)+20)/(2*4) or y = (20-400^(1/2))/(2*4)

y = 5 or y = 0

y in (-oo:0) U (0:5) U (5:+oo)

(8*y^2-(28*y))/(4*y^2-(20*y)) = 0

(8*y^2-28*y)/(4*y^2-20*y) = 0

8*y^2-28*y = 0

4*y*(2*y-7) = 0

2*y-7 = 0 // + 7

2*y = 7 // : 2

y = 7/2

4*y*(y-7/2) = 0

4*y^2-20*y = 0

4*y*(y-5) = 0

y-5 = 0 // + 5

y = 5

4*y*(y-5) = 0

(4*y*(y-7/2))/(4*y*(y-5)) = 0

( 4*y )

4*y = 0 // : 4

y = 0

( y-7/2 )

y-7/2 = 0 // + 7/2

y = 7/2

y in { 0}

y = 7/2

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